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(2x^2)+6x-920=0
a = 2; b = 6; c = -920;
Δ = b2-4ac
Δ = 62-4·2·(-920)
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7396}=86$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-86}{2*2}=\frac{-92}{4} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+86}{2*2}=\frac{80}{4} =20 $
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